 ### 新闻中心

NEWS CENTER

• 大型工业风扇降温的原理
• 本站编辑：杭州雅田机电有限公司发布日期：2019-06-02 16:59 浏览次数：

1、直径 730mm 的风扇：周长=0.73 × 3.14=2 .29m 截面积=0.36 × 0.36 × 3.14=0.407 平方米

2、直径 7200mm 的风扇 ：周长=7.2 × 3.14=22.9m 截面积=3.6 × 3.6 × 3.14=40.7 平方米 The large industrial ceiling fan is ideally operated, and you can imagine the wind blown out by the Super large industrial fan as a columnar air flow, and the outer surface of the columnar air flow will rub against the air. That resistance = K1(resistance constant) * perimeter ventilation = K2(velocity constant) * cross-sectional area. Take a 730mm diameter fan and a 7300mm diameter super large industrial fan for comparison:
1, 730mm diameter fan: perimeter = 0.73 × 3.14 = 2. 29M cross-sectional area = 0.36 × 0.36 × 3.14 = 0.407 square meters
2, 7200mm diameter fan: perimeter = 7.2 × 3.14 = 22.9 M cross-sectional area = 3.6 × 3.6 × 3.14 = 40.7 square meters
It can be seen that the resistance of large fans passing through the same area of air flow is 0.1 times that of small fans.
Principle: The friction force of the large airflow fluid movement is relatively small, so that the large fan can drive a large amount of air but the energy required by the small fan is relatively less! Once the inertia of the air is overcome, the self-movement of a large amount of air flow can enable it to maintain the continuous flow of air with only a small amount of subsequent power. The friction of the small fan is relatively large, and most of the energy is lost during the friction process.